Sides of triangle | Some Applications of Trigonometry | CBSE | Class 10 | Math show

Sides of triangle | Some Applications of Trigonometry | CBSE | Class 10 | Math

Summary: This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

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  • Artist: Shiksha Abhiyan
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Podcasts:

 Q5. In the given figure, angle ACB = 90 and CD is perpendicular to AB. Prove that CD x CD = BD. AD | File Type: audio/mpeg | Duration: 264

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

 Q4. The side AD of a parallelogram ABCD is produced to a point E. BE intersects CD at F. Show that triangle ABE is similar to triangle CFB. | File Type: audio/mpeg | Duration: 158

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

 Q3. In the given figure PA, QB and RC each is perpendicular to AC such that PA-x, RC y, QB=z, AB=a and BC=b. Prove that 1/x + 1/y = 1/z | File Type: audio/mpeg | Duration: 265

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

 Q2. In triangle ABC, AD is perpendicular to BC and AD x AD = BD.CD .Prove that angle BAC = 90. | File Type: audio/mpeg | Duration: 244

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

 Q1. Diagonals AC and BD of a trapezium ABCD with AB II DC intersect each other at point 0. Using similarity criteria for two triangles, show that OA/OC = OB/OD. | File Type: audio/mpeg | Duration: 164

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

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